# SOLUTION: I need assistance on completing the square in order graph the conic section. -9x^2+4y^2+36x+24y-36=0 Do you start off as -9x^2+4y^2+36x+24y=-36?

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 Question 250296: I need assistance on completing the square in order graph the conic section. -9x^2+4y^2+36x+24y-36=0 Do you start off as -9x^2+4y^2+36x+24y=-36?Found 2 solutions by richwmiller, Alan3354:Answer by richwmiller(9144)   (Show Source): You can put this solution on YOUR website!first put all the x's together and all the y's together then move the constant -36 to the other side then do the complete the square calculations first for x and then for y Answer by Alan3354(31513)   (Show Source): You can put this solution on YOUR website!-9x^2+4y^2+36x+24y-36=0 Do you start off as -9x^2+4y^2+36x+24y=-36 ---------------------- That's a good step 1. Group the x and y terms: -9x^2+36x + 4y^2+24y = -36 -(9x^2-36x) + 4y^2+24y = -36 Add coeffs to complete the squares: -(9x^2-36x+36) + (4y^2+24y+36) = -36 - 36 + 36 -(3x-6)^2 + (2y+6)^2 = -36 (2y+6)^2 - (3x-6)^2 = 36