SOLUTION: Find the vertices of the hyperbola 4x^2-16y^2=64

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Question 248091: Find the vertices of the hyperbola
4x^2-16y^2=64

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the vertices of the hyperbola
4x^2-16y^2=64
Divide thru by 64 to get:
x^2/16 - y^2/4 = 1
a = 4 ; b = 2
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Vertices: (-4,0); (4,0)
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Cheers,
Stan H.