SOLUTION: Find the vertices of the hyperbola 4x^2-16y^2=64

SOLUTION: Find the vertices of the hyperbola 4x^2-16y^2=64

Algebra.Com

Question 248091: Find the vertices of the hyperbola
4x^2-16y^2=64

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the vertices of the hyperbola
4x^2-16y^2=64
Divide thru by 64 to get:
x^2/16 - y^2/4 = 1
a = 4 ; b = 2
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Vertices: (-4,0); (4,0)
================================
Cheers,
Stan H.
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