SOLUTION: y^2-8y-8x-8=0 Find the equation of the axis. find the coordinates of the vertex. find the coordinates of the focus. find the equation of the directrix

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: y^2-8y-8x-8=0 Find the equation of the axis. find the coordinates of the vertex. find the coordinates of the focus. find the equation of the directrix      Log On

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Question 239273: y^2-8y-8x-8=0 Find the equation of the axis. find the coordinates of the vertex. find the coordinates of the focus. find the equation of the directrix
Answer by Photonjohn(42) About Me  (Show Source):
You can put this solution on YOUR website!
Complete the square for Y^2 and you get the equation,
(y-4)^2 = 8x + 24
The vertex is at (-3,4) and opens to the right.
You can find the rest from here.