SOLUTION: y^2-8y-8x-8=0 Find the equation of the axis. find the coordinates of the vertex. find the coordinates of the focus. find the equation of the directrix

Question 239273: y^2-8y-8x-8=0 Find the equation of the axis. find the coordinates of the vertex. find the coordinates of the focus. find the equation of the directrix
Answer by Photonjohn(42) (Show Source): You can put this solution on YOUR website!
Complete the square for Y^2 and you get the equation,
(y-4)^2 = 8x + 24
The vertex is at (-3,4) and opens to the right.
You can find the rest from here.
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