SOLUTION: x^2+4x-4y+16=0

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Question 238232: x^2+4x-4y+16=0
Answer by checkley77(12569) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+4x-4y+16=0
-4y=-x^2-4x-16
y=-x^2/4-4x/4+16/-4
y=-x^2/4-x-4
+graph%28+300%2C+200%2C+-6%2C+5%2C+-20%2C+10%2C+-x%5E2%2F4+-x+-4%29+ (graph 300x200 pixels, x from -6 to 5, y from -20 to 10, -x^2/4 -x -4).