You can
put this solution on YOUR website!Since now you know your new centre which is (2,2) and your a absolute value the equation goes like this:

all you have now to do is to find the absolute value for b.
since you know that the transverse axis is 6 ---> 6/2=3^2 = 9 (a value)
The centre is (h-a,k) and (h+a,k)
(6-2,2) and (6+2,2) -> the distance between these two points is 4 (b value)
Since 3^2 = 9 (b)
4^2=16 (a)
Now pulg the terms into the equation.
Hence, the equation for the hyperbola is