# SOLUTION: Can ANYONE help me with this problem? No one seems to know the foci of this equation. Please Help!!! (x^2/16)-(y^2/4)= 1 Thank You, Sarah

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: Can ANYONE help me with this problem? No one seems to know the foci of this equation. Please Help!!! (x^2/16)-(y^2/4)= 1 Thank You, Sarah      Log On

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 Algebra: Conic sections - ellipse, parabola, hyperbola Solvers Lessons Answers archive Quiz In Depth

 Question 202428: Can ANYONE help me with this problem? No one seems to know the foci of this equation. Please Help!!! (x^2/16)-(y^2/4)= 1 Thank You, SarahAnswer by jim_thompson5910(28595)   (Show Source): You can put this solution on YOUR website!This equation is a hyperbola in the form (this hyperbola opens left/right). The foci for any hyperbola in the form are (h+c,k) and (h-c,k) where In this case, , , (since ) and (since ) So ---> ---> which means that Now plug in the given h, k, and c values into (h+c,k) and (h-c,k) to get: and and simplify to get and So the foci are and Note: the foci approximate to (4.4722, 0) and (-4.4722, 0)