SOLUTION: How do you graph (x-4)^2/16-(y+4)^2/16=1

Question 198968This question is from textbook
: How do you graph (x-4)^2/16-(y+4)^2/16=1 This question is from textbook

Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How do you graph (x-4)^2/16-(y+4)^2/16=1
------------
I use the FREE software I dl'ed from
www.padowan.dk.com/graph/

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How do you graph (x-4)^2/16-(y+4)^2/16=1
It's a hyperbola with center at (4,-4)
When y = -4, (x-4)^2 = 16
So x-4 = 4 or x-4 = -4
x = 8 or x = 0
Gives you two points: (8,-4) and (0,-4)
------
When x = 4, -(y+4)^2 = 1
(y+4)^2 = -1
y is imaginary.
So the hyperbola does not cross the line x = 4.
-------------------
The hyperbola opens to the right from (8,-4) and
to the left from (0,-4)
=================================
Cheers,
Stan H.

RELATED QUESTIONS
How do you graph this?... (answered by lwsshak3)
graph... (answered by EdenWolf)
How do you graph {x^2-y^2=16} (answered by stanbon)
graph... (answered by Fombitz)
graph x^2/16 + y^2/4 = 1 (answered by stanbon)
Graph x^2/16 - y^2/4 =... (answered by Fombitz)
Graph x^2/16 - y^2/4 =... (answered by Alan3354)
graph x^2/4 + y^2/16... (answered by ikleyn)
How do you graph... (answered by Cody959)