SOLUTION: hyperbola (x+2)^2 ________ 25 (x+2)^2 ________ 25 minus (x+2)^2 ________ 25 equals 1 find the center, foci, vertices, length of the transv

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: hyperbola (x+2)^2 ________ 25 (x+2)^2 ________ 25 minus (x+2)^2 ________ 25 equals 1 find the center, foci, vertices, length of the transv      Log On


   

Question 195131: hyperbola
(x+2)^2
________
25
(x+2)^2
________
25
minus
(x+2)^2
________
25
equals
1
find the center, foci, vertices, length of the transverse and conjugate axis, and the asymtopes
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!


Sorry, but a hyperbols's equation is either



%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1



or



%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1



They both contain both x's and y's.

Yours is incorrect because it contains only x's.

You must have typed an x for a y.  Besides, you

have typed the first term twice.  If you will

re-post typing the problem carefully, then we

can help you.



Edwin