SOLUTION: Find the vertex, focus, directrix, and axis of symmetry of each parabola. x^2+8y+4x-4=0 We have been using the formulas y-k=a(x-h)^2 and x-h=a(y-k)^2 I don't understand which to

Question 193531This question is from textbook algebra and trigonometry structure and method book 2
: Find the vertex, focus, directrix, and axis of symmetry of each parabola.
x^2+8y+4x-4=0
We have been using the formulas y-k=a(x-h)^2 and x-h=a(y-k)^2 I don't understand which to use here, even after completing the square and its confusing because I don't know which is which. please explain and be specific. thank you. This question is from textbook algebra and trigonometry structure and method book 2

Found 2 solutions by Mathtut, jim_thompson5910:
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!

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a=coefficient of term so a=-1/8
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so vertex is (-2,0)
focus is (-2,0+1/4a)-->1/4a=1/(4(-1/8)=1/(-1/2)=-2--> (-2,-2)
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directrix is at y=-1/4a=-1/4(-1/8)=-1/(-1/2)=2 so y=2
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axis of symmetry is x=-2
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Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
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