SOLUTION: y=5(x+2)^2+7 for the parabola find: the vertex, focus, directrix line (line y=) length of the latux rectum

Algebra.Com
Question 191056: y=5(x+2)^2+7
for the parabola find:
the vertex,
focus,
directrix line (line y=)
length of the latux rectum

Answer by Mathtut(3670)   (Show Source): You can put this solution on YOUR website!
vertex is at (-2,7)
:
length of focus is 1/4(5)=1/20 so focus is at (-2,141/20) or(-2,7.05)
:
directrix is at y=139/20 or y=6.95
:
length of latux rectum is 4(1/20)=4/20=1/5

RELATED QUESTIONS

Find the focus, vertex, length of latus rectum,and the equation of directrix of the... (answered by josgarithmetic,greenestamps)
Given the equation of the parabola (x+2)^2=2(y-1), find the vertex, directrix, focus and... (answered by josgarithmetic)
PARABOLA: what's the vertex, focus, directrix, latus rectum and graph of the... (answered by solver91311)
(Y-2)^2= -16(x-3) Find the Vertex Focus Endpoints of latus rectum Directrix (answered by josgarithmetic)
The distance between the points (1,3) and (-2,7) is: 25 units units 7... (answered by stanbon)
Find the vertex, focus, length of latus rectum,and the equation of directrix of y^2 - 4y... (answered by josgarithmetic,greenestamps)
How do I find the vertex, focus, directrix, axis of symmetry, and latus rectum of this... (answered by Edwin McCravy)
Find the vertex, focus and directrix of the parabola ( x -5 )^2 = 8... (answered by josgarithmetic)
parabola,x^2 +6x -y +11 =0 find the vertex,focus and directrix of the... (answered by lwsshak3)