SOLUTION: Find the standard form of the circle x^2 + y^2 + 2x - 6y - 6 = 0 How do I solve this? Please help. Thank you.

Question 189071: Find the standard form of the circle x^2 + y^2 + 2x - 6y - 6 = 0
How do I solve this?
Please help.
Thank you.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the standard form of the circle x^2 + y^2 + 2x - 6y - 6 = 0
--------
Complete the square on the x-terms and on the y-terms:
(x^2 +2x + 1) + (y^2 -6y + 9) = 6 +1 + 9
-------------------------------------------
Change the forms:
(x+3)^2 + (y-3)^2 = 4^2
That is the standard form.
================================
Cheers,
Stan H.
RELATED QUESTIONS
Write the equation of the circle x^2+10x+y^2-6y+29=0 in standard form. Find the radius... (answered by Alan3354)

How do I find the standard form of a circle? The question states x^2 + Y^2 +6x - 6y (answered by fractalier)

Please help me!! I do not understand how to do this question! The equation of he... (answered by mananth)

what is the standard form, radius, and center of this circle equation:... (answered by Fombitz)

Could you please help me solve this? find the center (h,k) and radius r of the circle. I... (answered by josmiceli)

Please help me, I am lost. complete the square and write the equation in standard form.... (answered by solver91311)

Please help.... In the example below give the centre and radius of the circle.... (answered by jim_thompson5910,lwsshak3)

Help, Please! I am supposed to write a conic equation in STANDARD FORM for a circle... (answered by josgarithmetic)

Please help me with this problem: How do I put the following in standard form??... (answered by jim_thompson5910)