SOLUTION: find the equation for a circle with ends of its diameter at points p(5,1) and Q(7,3). Write the answer in standard form.
A. (x+3)^2+(y-2)^2=32
B. x^2+y^2=32
C. (x+6)^2+(y-2)^2
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Question 189017: find the equation for a circle with ends of its diameter at points p(5,1) and Q(7,3). Write the answer in standard form.
A. (x+3)^2+(y-2)^2=32
B. x^2+y^2=32
C. (x+6)^2+(y-2)^2=2
D. (x-6)^2+(y-2)^2=2
please choose A,B,C or D
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Use the mid-point formulas to calculate the coordinates of the mid-point of the diameter line segment which is the center of the circle.
where
 )
and )
are the coordinates of the given points.
Once you have the center determined, use the distance formula to calculate the distance from either given point to the center to determine the radius:
^2 + (y_1 - k)^2})
The equation of a circle with center at
 )
and radius r is
^2 + (y - k)^2 = r^2)
John
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