SOLUTION: Give the vertex, focus, directrix, and the distance across parabola at focus, and then graph the parabola. x^2+6x+2y+15=0

Question 188602: Give the vertex, focus, directrix, and the distance across parabola at focus, and then graph the parabola.
x^2+6x+2y+15=0
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!

:
vertex is at (-3,-3)
:
1/4p=-1/2
:
p=-1/2
:
directrix is at y=-5/2
focus is at (-3,-7/2)
:
distance across parabola is abs value of 4p which equals abs value of 4(-1/2)= 2:

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