SOLUTION: how do you find the points of intersection for x^2 + y^2=25 x + y^2=5

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: how do you find the points of intersection for x^2 + y^2=25 x + y^2=5      Log On

Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 185557: how do you find the points of intersection for
x^2 + y^2=25
x + y^2=5
Answer by edjones(7311) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + y^2=25
x + y^2=5
.
x=5-y^2
(5-y^2)^2+y^2=25 substitute 5-y^2 for x.
y^4-10y^2+25+y^2=25
y^4-9y^2=0
y^2(y^2-9)=0
y^2(y+3)(y-3)=0
y=0, x=5; y=3, x=-4; y=-3 x=4
.
Ed
.
graph%28500%2C500%2C-10%2C10%2C-10%2C10%2Csqrt%2825-x%5E2%29%2Csqrt%285-x%29%2C-sqrt%2825-x%5E2%29%2C-sqrt%285-x%29%29