SOLUTION: What is the standard form of the conic with the equation:
3x^2+5y^2-12x+30y+42=0
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Question 179193: What is the standard form of the conic with the equation:
3x^2+5y^2-12x+30y+42=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What is the standard form of the conic with the equation:
3x^2+5y^2-12x+30y+42=0
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Complete the square on the x-terms and on the y-terms separately:
3x^2 - 12 x + ? + 5y^2 + 30y + ? = -42 + ?
3(x^2 - 4x + 4) + 5(y^2 + 6y + 9) = -42 + 3*4 + 5*9
3(x-2)^2 + 5(y+3)^2 = 15
(x-2)^2/5 + (y+3)^2/3 = 1
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Cheers,
Stan H.
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