SOLUTION: i have the equation of an ellipse: (x-16)<-squared over 49 [plus](y-19)<-squared over 36 equals 1......i need help getting this to the "y= form" (y equals form) i explained it as b

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: i have the equation of an ellipse: (x-16)<-squared over 49 [plus](y-19)<-squared over 36 equals 1......i need help getting this to the "y= form" (y equals form) i explained it as b      Log On


   

Question 176984: i have the equation of an ellipse: (x-16)<-squared over 49 [plus](y-19)<-squared over 36 equals 1......i need help getting this to the "y= form" (y equals form) i explained it as best as i could so if you could please get back to me as soon as possible...gracias
Answer by gonzo(654) About Me  (Show Source):
You can put this solution on YOUR website!
i believe your equation is:
%28x-16%29%5E2%2F49+%2B+%28y-19%29%5E2%2F36+=+1
subtract %28x-16%29%5E2%2F49 from both sides of the equation to get:
%28y-19%29%5E2%2F36+=+1+-+%28x-16%29%5E2%2F49
multiply both sides of the equation by 36 to get:
%28y-19%29%5E2+=+36%2A%281+-+%28x-16%29%5E2%2F49%29
take the square root of both sides of the equation to get:
y-19 = +/- sqrt%2836%2A%281+-+%28x-16%29%5E2%2F49%29%29
add 19 to both sides of the equation to get:
y = +/- %28sqrt%2836%2A%281+-+%28x-16%29%5E2%2F49%29%29%29 + 19
note:
in order to graph this equation, you have to separate it into two equations, one equation taking the plus square root, and the other equation taking the minus square root as follows:
y+=+%28sqrt%2836%2A%281+-+%28x-16%29%5E2%2F49%29%29%29%2B+19
and:
y+=+-%28sqrt%2836%2A%281+-+%28x-16%29%5E2%2F49%29%29%29%2B+19
the first equation shows you the top of the ellipse. the second equation shows you the bottom of the ellipse.
a graph of the ellipse is shown below: