SOLUTION: i need the vertex, the axis of symmetry of this problem....y=-x^2+6x-5...i know i have to put in form y=a(x-h)^2+k but i am lost

SOLUTION: i need the vertex, the axis of symmetry of this problem....y=-x^2+6x-5...i know i have to put in form y=a(x-h)^2+k but i am lost

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Question 175102: i need the vertex, the axis of symmetry of this problem....y=-x^2+6x-5...i know i have to put in form y=a(x-h)^2+k but i am lost
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Actually, you don't need to put it in a different form.

For any parabola described by , the vertex is located at (,) and the equation of the axis of symmetry is . Just plug in your values and do the arithmetic.
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