SOLUTION: one of my questions read,given the following info, write the standard equation for each conic. 1. Hyperbola with a foci (-8,0) and (8,0) and verticies (-6,0) and(6,0)

Question 170285: one of my questions read,given the following info, write the standard equation for each conic.
1. Hyperbola with a foci (-8,0) and (8,0) and verticies (-6,0) and(6,0)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Take note that ALL of the points given to you (both vertices and foci) all have a y-coordinate of 0. So this tells us that the hyperbola opens left and right like this:

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Take note that the distance from the center to either focus is 8 units. So let's call this distance "c" (ie )

Remember, the equation of any hyperbola opening left/right is

So we need to find the values of h, k, a, and b

Now let's find the midpoint of the line connecting the vertices. This midpoint is the center of the hyperbola

x mid: Average the x-coordinates of the vertices:
So the x-coordinate of the center is 0. This means that h = 0
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y mid: Average the y-coordinates of the vertices:

So the y-coordinate of the center is 0. This means that k = 0

So the center is (0,0) which means that h=0 and k=0

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Now because the hyperbola opens left and right, this means that the vertices are (h+a,k) and (h-a,k). In other words, you add and subtract the value of "a" to the x-coordinate of the center to get the vertices.

Since the value of "h" and "k" is 0, this means that the vertices become (0+a,0) and (0-a,0) then simplify to (a,0) and (-a,0)

So this tells us that a=6 and -a=-6 which simply means that a=6

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Now it turns out that the value of "b" is closely connected to the values of "a" and "c". They are connected by the equation

Plug in and

Square 6 to get 36. Square 8 to get 64

Subtract 36 from both sides.

Subtract

Take the square root of both sides. Note: only the positive square root is considered (since a negative distance doesn't make sense)

Simplify the square root.

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Recap:

So we found the following: , (the x and y coordinates of the center), and

Start with the general equation for a hyperbola (one that opens left/right)

Plug in , , and

Square 6 to get 36. Square to get

Multiply

Simplify

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Answer:

So the equation of the hyperbola that has the foci (8,0) and (-8,0) along with the vertices (-6,0) and (6,0) is:

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