SOLUTION: im having trouble graphing out an finding the focus eccentricity,directrix an axis of symetry of this standard equation. (y-4)^2=8(x-6)

Question 170141: im having trouble graphing out an finding the focus eccentricity,directrix an axis of symetry of this standard equation.
(y-4)^2=8(x-6)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
finding the focus eccentricity,directrix an axis of symetry of this standard equation.
(y-4)^2=8(x-6)
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Vertex: (6,8)
4p = 8, so p = 2
The parabola opens to the right so focus at (8,8)
Axis of symmetry: y = 8
e = 1 for any parabola.
The directrix is perpendicular to the axis of symmetry and is "p"
to the left of the vertex. Its equation is x = 4
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Cheers,
Stan H.

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