SOLUTION: Find the length of the major axis for the graph of 49x^2 + 16y^2 = 784
I'm struggling with this one. Any help would be appreciated.
Thank you
Michele
Algebra.Com
Question 170009: Find the length of the major axis for the graph of 49x^2 + 16y^2 = 784
I'm struggling with this one. Any help would be appreciated.
Thank you
Michele
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation
Divide both sides by 784. The goal here is to make the right side equal to 1
Simplify
Break up the fraction
Reduce
Rewrite 16 as . Rewrite 49 as
Now the equation is in the form where , , , and .
The values of "a" and "b" are the lengths of the major and minor axis. If "a" is larger than "b", then is the length of the major axis. On the other hand, if "b" is larger than "a", then is the length of the major axis.
Since , this means that the length of the major axis is .
So multiply the value of "b" by 2 to get
So the length of the major axis is 14 units
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