SOLUTION: What is the center of the hyperbola whose equation is [(x+3)^2 / 9] - [(y-3)^2 / 16] = 1? I know the fomula would be (x-h)^2 / a^2 - (y-k)^2 / b^2 = 1. Would the answer be(-3

Question 162750: What is the center of the hyperbola whose equation is [(x+3)^2 / 9] - [(y-3)^2 / 16] = 1?
I know the fomula would be (x-h)^2 / a^2 - (y-k)^2 / b^2 = 1.
Would the answer be(-3,3)? I would love to know the correct answer. Thank you so much for your help!
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Since you can rewrite:
[(x+3)^2 / 9] - [(y-3)^2 / 16] = 1
as
[(x-(-3))^2 / 9] - [(y-3)^2 / 16] = 1
So, as you can see:
(h,k) = (-3, 3)
.
So, YES, you are right.
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