SOLUTION: 14. What is the standard equation of the circle whose center is (-5,-4) and whose radius is 3? (x-h)^2 + (y-k)^2 = r^2. (x-5)^2+(y-4)^2=3^2 I know this problem has sign err

Question 162555: 14. What is the standard equation of the circle whose center is (-5,-4) and whose radius is 3?
(x-h)^2 + (y-k)^2 = r^2.
(x-5)^2+(y-4)^2=3^2
I know this problem has sign errors, but i cant see what it is that Im doing wrong. If someone could tell me where my mistake is at, I would really apperciate it :). Thank you.
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
(-5,-4) h=-5, k=-4
(x-h)^2+(y-k)^2=r^2.
(x-[-5])^2+(y-[-4])^2=3^2
(x+5)^2+(y+4)^2=3^2

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