SOLUTION: 11. What is the center of the ellipse whose equation is (x^2)/25 + (y^2)/4 = 1? A (25,1) B (5,1) C (4,25) D (4,1) E (0,0) F (5,2) (x-h)^2 / a^2 + (y-k)^2 / b^2 =

Question 162020: 11. What is the center of the ellipse whose equation is (x^2)/25 + (y^2)/4 = 1?
A (25,1)
B (5,1)
C (4,25)
D (4,1)
E (0,0)
F (5,2)

(x-h)^2 / a^2 + (y-k)^2 / b^2 = 1 I tried to used this equation to help, but im really stuck. I appericaite any help you can offer. Thank you!

Found 2 solutions by scott8148, jim_thompson5910:
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
from the given equation, h and k are both zero __ a and b have nothing to do with the center

E looks good...
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You have the right idea, but it might help to go even further

Start with the given equation

Replace with . Replace with . This is possible since adding/subtracting zero doesn't affect the equation

Rewrite as . Rewrite as .

Notice how the equation above fits the form where in this case , , , and .

Remember the center is simply (h,k). So this means that the center is (0,0). So the answer is E

Note: If you are really stuck, you can solve for "y" and graph. Once you do that, you'll see that the center is at (0,0)
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