# SOLUTION: could somebody help, me please? 1)find the center and length of a radius of each circle a) x^2+y^2+8x-12x+43=0 I tried. and got stuck (x^2+8x)+(y^2-12y)=-43 (x^2+8x=43)^2 +

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: could somebody help, me please? 1)find the center and length of a radius of each circle a) x^2+y^2+8x-12x+43=0 I tried. and got stuck (x^2+8x)+(y^2-12y)=-43 (x^2+8x=43)^2 +       Log On

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 Question 156547This question is from textbook college algebra : could somebody help, me please? 1)find the center and length of a radius of each circle a) x^2+y^2+8x-12x+43=0 I tried. and got stuck (x^2+8x)+(y^2-12y)=-43 (x^2+8x=43)^2 + (y^2-12y+12)^2=-43+43+12 then....This question is from textbook college algebra Answer by oscargut(891)   (Show Source): You can put this solution on YOUR website! then then (completing squares) then center is (-4,6) and radius is 3 You can do the exercises using formulas too