SOLUTION: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM:
Complete the square and write the equation in standard form. Then give the center and radius of the circle. x^2 + y^2 - 2x - 4y -4
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Question 156163: CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM:
Complete the square and write the equation in standard form. Then give the center and radius of the circle. x^2 + y^2 - 2x - 4y -4 = 0.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given equation
Rearrange the terms (place the "x" and "y" terms together)
Take half of the "x" coefficient and square it to get . Add this to both sides (note: add the one right after the -2x)
Take half of the "y" coefficient and square it to get . Add this to both sides (note: add the four right after the -4y)
Combine like terms on the right side
Group the terms into two groups of three terms in each
Factor to get
Factor to get
Add 4 to both sides
Now we have an equation in the form of where , , and . Remember, for the general circle , the center is (h,k) and and the radius is "r"
So for , the center is (1,2) and the radius is 3 units
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