SOLUTION: I'm not sure the answer I got for this is right. Find the vertex and axis of symmetry of the following parabola. f(x) = x^2 - 6x + 11 My work: (-3) ^2 y = (x-3)^2 + 11

Question 153157: I'm not sure the answer I got for this is right.
Find the vertex and axis of symmetry of the following parabola.
f(x) = x^2 - 6x + 11
My work:
(-3) ^2
y = (x-3)^2 + 11 - 9
y = (x-3)^2 +2
a = 1
h =3
k = 2
Vertex : (3,2)
No asymptotes
Can anyone tell me if this is correct and point me in the right direction if it isn't?
Thanks!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the vertex and axis of symmetry of the following parabola.
f(x) = x^2 - 6x + 11
x^2-6x+9 = y - 11 + 9
(x-3)^2 = y-2
---------------
Axis of symmetry at x = 3
Vertex: (3,2)
===================
Cheers,
Stan H.
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