SOLUTION: graph f(x)=-x^2+3x+2 and find the vertex.
Algebra.Com
Question 150469: graph f(x)=-x^2+3x+2 and find the vertex.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
graph f(x)=-x^2+3x+2 and find the vertex.
---------------
The vertex occurs where x = -b/2a = -3/(2*-1) = 3/2
and f(3/2) = -(3/2)^2+3*(3/2)+2 = -9/4 + 18/4 + 8/4 = 17/4
--------------------------
===================
Cheers,
Stan H.
RELATED QUESTIONS
Find the vertex and axis of symmetry of the graph of the function.
f(x) = -3x^2 - 6x - (answered by stanbon,MathTherapy)
Find the vertex and than graph
y= f(x)=2x^2+8x+16... (answered by Fombitz)
Find the vertex and the axis of symmetry for the following graph:... (answered by jim_thompson5910)
Write the equation of the parabola with the shape as f(x)=-2x^2, but with the vertex... (answered by lwsshak3)
find the vertex of:... (answered by stanbon)
graph f(x)=-x^2-8x-15 and find the... (answered by mananth)
Find the vertex and axis of symmetry of the graph of the function.
f(x) = -3x^2 - 6x - (answered by josgarithmetic,MathTherapy)
Find the label the vertex and the line of symmetry. Graph the function... (answered by Fombitz)
Find and label the vertex and the line of symmetry. Graph the function.
{{{f(x)=3x^2}}}
(answered by Earlsdon)