SOLUTION: Help I am trying to fully understand how to find the real solutions of the system. I have no problem solving a problem like : x^2+2y^2=12 and 3x^2-y^2=8 but when the problem looks

Question 145751: Help I am trying to fully understand how to find the real solutions of the system. I have no problem solving a problem like : x^2+2y^2=12 and 3x^2-y^2=8 but when the problem looks like this: xy+6=0 and x-y=-5 I cant figure out where to start. Your help would do a lot for me thanks.
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
xy+6=0
x-y=-5 then x=y-5
then using the 1st eq we have (y-5)y+6=0 then y^2-5y+6=0
solving this eq solutions are 3 and 2 so y=2 or y=3
if y=2 then x=-3
if y=3 then x=-2
Solutions are (-3,2) and (-2,3)

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