SOLUTION: What is the focus of the parabola with the equation (x - 1)^2 + 32= 8y?
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Question 145225: What is the focus of the parabola with the equation (x - 1)^2 + 32= 8y?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The equation of a parabola with axis parallel to the y-axis, vertex at (h,k), and focus at (h,k+p) is:
So, rearrange the given equation:
Add to both sides:
Factor the 8 out of the right hand expression:
That puts the equation into the given form and you can see by inspection that the vertex is at (1,4)
Since , and the focus is at (1,6)
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