SOLUTION: The vertex of the parabola below is at the point (1, 3) and the point (2, 6) is on the parabola. What is the equation of the parabola?
i had gotten y = 6(x - 1)^2 + 3 but it cam
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Question 144994: The vertex of the parabola below is at the point (1, 3) and the point (2, 6) is on the parabola. What is the equation of the parabola?
i had gotten y = 6(x - 1)^2 + 3 but it came out wrong.
these are the other options
A. y = 3(x + 1)^2 - 3
C. y = 3(x - 1)^2 + 3
D. x = 2(y - 3)^2 + 1
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Since the vertex is (1,3) this means
Now plug in and
Subtract
Square 1 to get 1
Multiply
Subtract 3 from both sides
So the equation is which means that the answer is choice C)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The vertex of the parabola below is at the point (1, 3) and the point (2, 6) is on the parabola. What is the equation of the parabola?
i had gotten y = 6(x - 1)^2 + 3 but it came out wrong.
these are the other options
A. y = 3(x + 1)^2 - 3
C. y = 3(x - 1)^2 + 3
D. x = 2(y - 3)^2 + 1
---------------------
Form:
y = a(x-h)^2 + k
6 = a(2-1)^2 + 3
6 = a+3
a = 3
-------------
EQUATION:
y = 3(x-1)^2+3
Answer: C
================
Cheers,
Stan H.
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