SOLUTION: The equation below is a circle. What is the y-coordinate of the center of the circle? (x - 6)2 + (y + 5)2 = 152 my initial awnser was 5 but i got it wrong!

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: The equation below is a circle. What is the y-coordinate of the center of the circle? (x - 6)2 + (y + 5)2 = 152 my initial awnser was 5 but i got it wrong!      Log On

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Question 144902: The equation below is a circle. What is the y-coordinate of the center of the circle?
(x - 6)2 + (y + 5)2 = 152
my initial awnser was 5 but i got it wrong!
Answer by Alan3354(21615) About Me  (Show Source):
You can put this solution on YOUR website!
It's -5. The center is at (6,-5)
The form is (x-a)^2 + (y-b)^2 = r^2
That is a circle of radius r with its center at (a,b)