SOLUTION: Hello. Can I please get help with this problem? Give the focus, directix, and axis for the equation of the parabola y^2=-16x Thank you so much for your help!

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: Hello. Can I please get help with this problem? Give the focus, directix, and axis for the equation of the parabola y^2=-16x Thank you so much for your help!      Log On

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Question 140954This question is from textbook College Algebra
: Hello. Can I please get help with this problem?
Give the focus, directix, and axis for the equation of the parabola y^2=-16x
Thank you so much for your help!This question is from textbook College Algebra

Answer by checkley77(12569) About Me  (Show Source):
You can put this solution on YOUR website!
y^2=-16x
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2Cy+=+sqrt%28-16x%29%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, y = sqrt(-16x)).