SOLUTION: how do we do to solve 2q^2+14q=2q-q^2-9 ? i get stuck when trying to factor i am LOST please help

SOLUTION: how do we do to solve 2q^2+14q=2q-q^2-9 ? i get stuck when trying to factor i am LOST please help

Algebra.Com

Question 1393: how do we do to solve 2q^2+14q=2q-q^2-9 ? i get stuck when trying to factor i am LOST please help
Answer by usyim88hk(158) (Show Source): You can put this solution on YOUR website!
2q^2+14q = 2q-q^2-9
First we should put all the numbers on one side
2q^2+q^2-2q+14q+9 = 0
3q^2+12q+9 = 0
Now we can use the quadratic formula

x = -6/6 or -18/6
x = -1 or -3
RELATED QUESTIONS
I am trying to solve the quadratic equation 3x-12. When I factor out the binomial I get... (answered by richwmiller)

q^2-q-1 / q^3 - 2q^2+2q-1 / q^3 Trying to help my nephew, thank... (answered by ewatrrr)

Please HELP! I am stuck on these 4 problems!!! I need to find the factors of the... (answered by scott8148)

How do we solve 2q^3 - 8q^2 - 4950 =... (answered by vleith)

I am trying to factor -x^2-14x-13. please help me i am... (answered by checkley71)

Please help I am lost I do not understand how to factor the following binomials 64y^2- (answered by scott8148)

When the positive integer n is divided by 7, the quotient is q and the remainder is 4.... (answered by Edwin McCravy)

hello i am trying to solve -2[3j] -8 <= -20 i am stuck. how do i solve... (answered by tommyt3rd)

Hello... I am trying to figure out what q is when 0 = -2q^2 + 820q - 8000 I can see (answered by mananth)