SOLUTION: I NEED HELP ON THIS EQUATION COULD YOU HELP ME PLEASE?
{{{4X^2+Y^2-8X+6Y-3=0}}}
Transform equation by completing the square and graph.
{{{(4X^2-8X)+(Y^2+6Y)=3}}}
{{{4(X^2+2
Algebra.Com
Question 135569: I NEED HELP ON THIS EQUATION COULD YOU HELP ME PLEASE?
Transform equation by completing the square and graph.
WHAT DO I DO AFTERWARDS?
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
(4X^2-8X)+(Y^2+6Y)=3
4(X^2-2X+1)+(Y^2+6Y+9)=3+4+9
4(X-1)^2+(Y+3)^2=16
That is i the form of a circle with radius 4, centered at (1,-3)
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