SOLUTION: following equation defines a relation (x,y). Write the domain and range of each relation. x^2/9 + y^2/16 = 1

Question 134982: following equation defines a relation (x,y). Write the domain and range of each relation.
x^2/9 + y^2/16 = 1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Write the domain and range of each relation.
x^2/9 + y^2/16 = 1
(y^2/16) = 1 - (x^2/9)
y^2 = 16[1-(x^2/9)]
y = +-4sqrt[1-(x^2/9)]
-----------------------
Domain: All Real Numbers between -3 and 3
Range: All Real Numbers between -4 and 4
==========================================
RELATED QUESTIONS
Decide whether the relation defines y as a function of x. Give the domain and range. (answered by greenestamps,math_tutor2020)

Graph the relation defined by the equation x^2+(y-3)^2 = 16 . Express the domain and the... (answered by lwsshak3)

Determine whether the following relation is a function. Then state domain and range: X=... (answered by Fombitz)

Give the domain and range of the relation. Y=(x-1)^2+1 (answered by lwsshak3)

state the range and domain for the relation y=x^2+2. Is the relation also a fuction? (answered by robertb)

Graph each relation, and state its domain and range.... (answered by stanbon)

Determine whether the relation defines y as a function of x. Give the domain. 7x=2-7y (answered by solver91311)

The relation y=x^2-2 defines y as a function of x. True or... (answered by MathLover1)

Determine the domain and range of each relation... (answered by venugopalramana)