# SOLUTION: Write each equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse or hyperbola. Then graph the equation. 9x^2-36x+36=4y^2+24y+72

Algebra ->  Algebra  -> Quadratic-relations-and-conic-sections -> SOLUTION: Write each equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse or hyperbola. Then graph the equation. 9x^2-36x+36=4y^2+24y+72      Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Algebra: Conic sections - ellipse, parabola, hyperbola Solvers Lessons Answers archive Quiz In Depth

 Question 134932This question is from textbook : Write each equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse or hyperbola. Then graph the equation. 9x^2-36x+36=4y^2+24y+72This question is from textbook Answer by stanbon(57967)   (Show Source): You can put this solution on YOUR website!Write each equation in standard form. State whether the graph of the equation is a parabola, circle, ellipse or hyperbola. Then graph the equation. 9x^2-36x+36=4y^2+24y+72 Complete square on the x-terms and on the y-terms separately: 9(x^2-4x+4) = 4(y^2+6y+9) + 36 Divide thru by 36 to get: [(x-2)^2/4] - [(y-3)^2/9] = 1 ------------------------------------ Hyperbola ----------------------------------------- Can't graph it on this site; only functions can be graphed. The center of the hyperbola is (2,3) The hyperbola opens to the left and to the right The horizontal distance between the two vertices is 4 ============================================= Cheers, Stan H.