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Question 126660: **Sorry if this appears twice, it doesn't seem to have worked the first time.
A hyperbola with the transverse axis on the line y=-5, length of transverse axis = 6, conjugate axis on the line x = 2, and length of conjugate axis = 6.
I need to use this information and put this hyperbola into an equation in the Ax2+By^2+cxy+Dx+Ey+F=0
So far, I know that the center is at (2,-5) and both a and b = 3. (at least I think)
I am really having problems putting it into the form that they ask. Help would be greatly appreciated!!
Answer by solver91311(24713) (Show Source):
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