SOLUTION: I am trying to find the vertex and intercepts so that I can graph the parabols I have gotten this far and my mind has gone totally blank. the equation reads ----- y = x^2 +2x

Question 12488: I am trying to find the vertex and intercepts so that I can graph the parabols I have gotten this far and my mind has gone totally blank.

the equation reads ----- y = x^2 +2x -3
-b/2a = -2/3
when I insert in the equation I get 4/9 + 24/9 - 33/9
which gives me -5/9
now I am lost
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
You had the right idea for finding the vertex of the parabola but got the wrong answer.
Here: a = 1, b = 2, and c = -3, so:
= -1 So the x-coordinate of the vertex is -1. To find the y-coordinate, substitute -1 for x in the equation and solve for y.

The y-coordinate is -4.
The vertex is at (-1, -4)
The x-intercepts are found by setting y = 0 and solving for x (there will be two of them).
Solve by factoring.

and
and
The y-intercept is found by setting x = 0 and solving for y.

Let's see what the graph look like:

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