The equation of a circle with center at (h,k) and radius r is:
In your first example, you could re-write the equation as
Therefore h = 0 and k = 0 so the center is at (0,0) and the radius is 10
The second example is a trivial application of what I just showed you,
so you can do that one yourself.
The third one has the slight twist that , so
The fourth one is a bit trickier. You need to complete the square for each of the variables
First rearrange:
Now, what constant, p, do you need to add so that is a perfect
square? Let's try 4. . So add 4 to both sides of
the equation.
Next, look at the y terms. If we add 1, , so add 1 to
both sides of the equation.
Collect terms on the right, and factor the x and y parts of the left
Remember the minus signs in the standard circle equation,
That means we need to re-write the x part:
Now we have the circle's parameters directly: Center at (-2,1), radius = 3
Using the process I just showed you for the fourth example, you should be able
to solve the fifth one as soon as you determine whether the equal sign between
the and terms should be a plus sign or a minus sign.
(Did you hit the adjacent key or forget to shift?)
Hope that helps,
John