SOLUTION: show that 2x ^ 2 + 3y^2 - x + 2y + 1 = 0 is a circle

Question 1207523: show that 2x ^ 2 + 3y^2 - x + 2y + 1 = 0 is a circle
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

a circle formula is

so, complete squares in given equation

for part
for part

as you can see, we cannot get a formula of a circle which means given equation is NOT a circle

Answer by ikleyn(52834) (Show Source): You can put this solution on YOUR website!
.

Wrong formulation.

Having different coefficients at x^2 and y^2, this equation CAN NOT be an equation of a circle.

After transformations, this equation defines the EMPTY set of points.

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