SOLUTION: The span of the parabolic arch in Figure B is 8 m. At a distance of 2 m from the center, the vertical clearance is 4.5 m. Find the height of the arch. Hint: Choose a convenient coo

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Question 1206318: The span of the parabolic arch in Figure B is 8 m. At a distance of 2 m from the center, the vertical clearance is 4.5 m. Find the height of the arch. Hint: Choose a convenient coordinate system in which the equation of the parabola will have the form x2 4p(y k). Figure B: https://ctrl.vi/i/z9urPS17M

Found 2 solutions by ikleyn, math_tutor2020:
Answer by ikleyn(52814)   (Show Source): You can put this solution on YOUR website!
.
The span of the parabolic arch in Figure B is 8 m.
At a distance of 2 m from the center, the vertical clearance is 4.5 m.
Find the height of the arch.
Hint: Choose a convenient coordinate system in which the equation of the parabola
will have the form x2 4p(y k). Figure B: https://ctrl.vi/i/z9urPS17M
~~~~~~~~~~~~~~~~~~~~~~~


        I will solve the problem, but will not follow the hint,
        because I have better way to solve.


Place the origin of the coordinate system at the ground, where the left branch
of the parabola meets the ground.


Then the parabola has left x-intercept at x= 0 and right x-intercept at x= 8.

So, I can write the parabola equation in the form  

    y(x) = -a*(x-0)*(x-8),  or  y = -ax*(x-8).


Here "a" is some positive real number.  With the sign "-" before "a", the parabola is opened downward.

The parameter "a" is the only unknown now, and now my task is to find its value.


About this parabola, I know that the value y(x) at x = 6 is 4.5; so I write this equation

    y(6) = 4.5.


It is the same as

    -a*6*(6-8) = 4.5,  or  -6a*(-2) = 4.5,  or  12a = 4.5.


From this equation, I find  a =  =  =  = 0.375.


So, the parabola equation is y(x) = -0.375x*(x-8).


The maximum height is at x= 4:   = y(4) = -0.375*4*(4-8) = -0.375*4(-4) = 0.375*16 = 6.


ANSWER.  The maximum height of the arch is 6 meters.

Solved.

======================

When people from outside ask me to solve a problem, I don't like to use
somebodies' hints - because often I have my own, much better plan/idea/solution in my head.


///////////////////


If you want to see many other similar and different solved problems, look into the lesson
    - Word problems on engineering constructions of parabolic shapes
in this site.

You will find there complete solutions with detailed explanations,
so you will be able to learn the entire subject from there.


Happy learning  ( ! )



Answer by math_tutor2020(3817)   (Show Source): You can put this solution on YOUR website!

This is a supplement to tutor @ikleyn's solution.
https://www.desmos.com/calculator/9ivvmxaczq
Desmos is a graphing tool I use all the time. GeoGebra is another similar tool. Both are free.

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