SOLUTION: Find the focal diameter for the parabola 34.8y = x^2

Question 1204030: Find the focal diameter for the parabola 34.8y = x^2

Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

comparing to , we have
(,)=(,)
=> =>
then
focus: (,)
vertex: (,)
semi-axis length:
focal parameter:
eccentricity:
directrix:
Focal parameter (the distance between the focus to the directrix) is .

RELATED QUESTIONS
Find the focus, directrix, and focal diameter of the parabola. 9x + 7y2 = 0 focus (x,... (answered by Fombitz)

Find the focus, directrix, and focal diameter of the parabola. 4x^2 +11y =... (answered by lwsshak3)

Find the vertex, focus, directrix, and focal width of the parabola. -1/40 x^2=... (answered by josgarithmetic)

x=-2y^2 whats the directrix focal diameter, and... (answered by macston)

Find the vertex, focus, directrix, and focal width of the parabola. Show the graph. {{{... (answered by MathLover1)

if you are given a parabola and the focal diameter is 12, how do you find what the focus... (answered by lwsshak3)

What is the vertex, directrix, and focal width of the parabola:... (answered by lwsshak3)

what is the focal diameter of:... (answered by lwsshak3)

y=5x^2 whats the directrix,focal diameter and... (answered by josgarithmetic)