SOLUTION: Find the coordinates of the focus for the parabola y=x^2 + 5x -2

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Question 1197655: Find the coordinates of the focus for the parabola y=x^2 + 5x -2
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi  
the vertex form of a Parabola opening up(a>0) or down(a<0), 
y=a%28x-h%29%5E2+%2Bk 
where(h,k) is the vertex  and  x = h  is the Line of Symmetry , 
the focus is (h,k + p), With Directrix y = (k - p), a = 1/(4p)

y=x^2 + 5x -2
y = (x -(5/2)^2 - 25/4 - 2 = (x -(5/2))^2  -33/4  \Vertex form
V(-5/2, -33/4) p = 1/4  |the focus is (h,k + p)
F(-5/2, -32/4)
  


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