SOLUTION: Find the vertex, focus, and directrix of the parabola X^2-4X- 4Y +16=0. Solve and graph

Question 1194362: Find the vertex, focus, and directrix of the parabola X^2-4X- 4Y +16=0. Solve and graph
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!

preferring all lower case,

With this, if you compare to (x-h)^2=4p(y-k), then p=1, or the focus and directrix each is 1 unit from the vertex;
and
for your example,
====================================================================
vertex (2,3)
parabola is with vertical symmetry axis with vertex as minimum;
focus (2,4)
directrix y=2
====================================================================
RELATED QUESTIONS
Find the vertex, focus, and directrix of the parabola given by the equation x^2 + 4x + 4y (answered by KMST)

Find the vertex, focus, and directrix of the parabola.... (answered by lwsshak3)

find the vertex, focus, and directrix of the parabola given by each equation. Sketch the... (answered by josgarithmetic)

Please help me solve this equation Find the Parabola properties and graph x^2+4x+2y=0 (answered by rothauserc)

find the vertex, focus, and directrix of the parabola and sketch its graph. the equation (answered by richwmiller)

Find the vertex, focus, and directrix of the parabola... (answered by Mathtut)

Find the vertex, focus and directrix of the parabola and sketch the graph... (answered by josgarithmetic)

find the vertex, focus, directrix of the parabola by x^2 -4x -6y -16 =... (answered by Nate,stanbon)

parabola,x^2 +6x -y +11 =0 find the vertex,focus and directrix of the... (answered by lwsshak3)