SOLUTION: The vertices of a hyperbola are the points (−3, 2) and (−3, −2) and the length of its conjugate is 6. Find the equation of the hyperbola, the coordinates of its foci, and it

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Question 1194067: The vertices of a hyperbola are the points (−3, 2) and (−3, −2) and the length of its conjugate is 6.
Find the equation of the hyperbola, the coordinates of its foci, and its eccentricity.

Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
.
The vertices of a hyperbola are the points (−3, 2) and (−3, −2) and the length of its conjugate is 6.
Find the equation of the hyperbola, the coordinates of its foci, and its eccentricity.
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From the given info, the center of the hyperbola is the point (-3,0)

and its real axis lies on vertical line x = -3.


    Thus the hyperbola is "vertical", opened up and down.  


Real semi-axis length is half the distance between the vertices  a =  =  = 2.


Also, from the given part, the length of its conjugate axis is 6; hence, conjugate semi-axis length is  b = 6/2 = 3.


Now the standard form equation of the hyperbola is

     -  = 1.    ANSWER


                            P L O T


    


                 Hyperbola  -  = 1



In the plot, we can not see the imaginary axis and imaginary semi-axes: they are invisible.  

But we can show the foci.  They are  (,)  and  (,),  where 13 =  +  =  + .

Solved.



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