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A point moves so that its distance from the point (2,-1) is equal to its distance from the x-axis.
Find the equation of the locus.
a. x^2 - 4x - 4y + 4 = 0
b. y^2 - 4x - 2y + 5 = 0
c. x^2 - 4x - 2y + 5 = 0
d. x^2 + 4x - 2y + 5 = 0
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An equation of the locus is
= |y|. (notice the absolute value sign in the right side !)
Square both sides of the equation
(x-2)^2 + (y+1)^2 = y^2
Simplify
x^2 - 4x + 4 + y^2 + 2y + 1 = y^2
x^2 - 4x + 2y + 5 = 0.
ANSWER. The equation of the locus is x^2 - 4x + 2y + 5 = 0.
No one of the listed in the options list.
Solved.