SOLUTION: vertices: (15, 1), (-1, 1); Endpoints of Conjugate Axis: (7, 7), (7, -5)

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Question 1187958: vertices: (15, 1), (-1, 1); Endpoints of Conjugate Axis: (7, 7), (7, -5)


Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Vertices: (15, 1), (-1, 1); Endpoints of Conjugate Axis: (7, 7), (7, -5)

This is a hyperbola with branches opening right and left; the equation is of the form

%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1

(h,k) is the center: halfway between the two vertices, or the midpoint of the conjugate axis

a is the distance from the center to each vertex

b is the distance from the center to each end of the conjugate axis

With the given information, only simple calculations are needed to find h, k, a, and b and thus find the equation.

I leave it to you to do that.