SOLUTION: vertices: (15, 1), (-1, 1); Endpoints of Conjugate Axis: (7, 7), (7, -5)
Algebra.Com
Question 1187958: vertices: (15, 1), (-1, 1); Endpoints of Conjugate Axis: (7, 7), (7, -5)
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Vertices: (15, 1), (-1, 1); Endpoints of Conjugate Axis: (7, 7), (7, -5)
This is a hyperbola with branches opening right and left; the equation is of the form
(h,k) is the center: halfway between the two vertices, or the midpoint of the conjugate axis
a is the distance from the center to each vertex
b is the distance from the center to each end of the conjugate axis
With the given information, only simple calculations are needed to find h, k, a, and b and thus find the equation.
I leave it to you to do that.
RELATED QUESTIONS
Vertices: (15, 1), (-1, 1); Endpoints of Conjugate Axis: (7, 7),
(7, -5)
(answered by MathLover1,ikleyn)
Hi I need your help I'm struggling with solving this. Find the equation of the hyperbola, (answered by greenestamps)
Given vertices (2,-1) and (-16,-1) and endpoints of conjugate axis, (-7,5) and (-7,-7)... (answered by lwsshak3)
Dear Sir/Ma'am
Please help me solve this problem.
Given the equation... (answered by MathLover1)
Please help me solve this problem
Convert the General Equation... (answered by MathLover1)
Use the following hyperbola to answer all questions.
Find the center, foci, vertices,... (answered by Edwin McCravy)
find the answers of the following:
ellipse:
4X^2+y^2+8X-4y-92=0 find its... (answered by jsmallt9)
How can someone write an equation for a hyperbola using characteristics such as the foci: (answered by lwsshak3)
A diameter has endpoints at (7, 3) and (1,... (answered by solver91311,Alan3354)